The first key to this question was to realize that the functions gather
and spread
are called with a parantheses.
Okay to omit -e
in the first solution.
grep -n -e 'gather(\|spread(' *.R*
or grep -n -E 'gather\(|spread\(' *.R*
On the in-class midterm, we were not looking for -n
though it is good to include it.
Here are nother solutions from your peers, each using a pipe:
*grep -n '^[^#]' *.R* | grep -e 'gather(\|spread('*
or, similarly,
grep -e 'gather(\|spread('* *.{R, Rmd} | grep -v "^[^#]"
.
These answers assumes this was independent of part “b”.
Option 1.
Orange %>%
group_by(Tree) %>%
filter( age == max(age) ) %>%
ungroup() %>%
summarize( avg_growth_rate = mean( circumference / age ) ) #mutate okay too
Option 2.
Orange %>%
group_by(Tree) %>%
summarize( growth_rate = max(circumference) / max(age) ) %>%
summarize( avg_growth_rate = mean(growth_rate) )
Option 3.
Orange %>%
arrange(Tree, age) %>%
group_by(Tree) %>%
summarize( growth_rate = circumference[n()] / age[n()] ) %>%
summarize( avg_growth_rate = mean(growth_rate) )
Please refer to q5_solutions.R
at the course repo for the solution.
runs = sim_nine(n * 9, team = team)
dim(runs) = c(9, n)
colSums(runs)
runs_mw = mean(games_mw)
runs_dd = mean(games_dd)
runs_tt = mean(games_tt)
mw_wins = 81 * mean(mw_vs_dd == 'mw') + 81 * mean(mw_vs_tt == 'mw')
dd_wins = 81 * mean(mw_vs_dd == 'dd') + 81 * mean(dd_vs_tt == 'dd')
tt_wins = 81 * mean(mw_vs_tt == 'tt') + 81 * mean(dd_vs_tt == 'tt')